Question

A father has 3 sons. having age difference of 3 years .the total age of 3 sons is 24 years . the age of the youngest son is​

Answer 1

Answer:

5 years

Step-by-step explanation:

let age of first son be x.

the other sons will be x+3 and x+6

as they have 3 years gap.

x + x +3 +x +6 = 24

3x +9 = 24

3x = 15

x =5

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Answer 2

Answer:

let the eldest, middle and youngest sons be A,B and C respectively..

and the age of A be x

so age of B = 3+x

and age of C is = 6+x

given that x+3+x+6+x = 24

3x+9 = 24

3x = 15

x= 5

thus the age of youngest son is 6+5

= 11years