Question

A father has tipple 5 years ago to his son after five years he has double to his son what is the present age of father and his son​

Answer 1

Answer:

Suppose present age of father is F

and son's age is B

So 5 years ago

F-5=3(B-15)=3B-45.....(1)

and after 5 years

F+5=2(B+5)=2B+10.....(2)

subtracting second equation from first, we get:

-10=B-45+10

So B=45-10-10

=25......ANSWER

Put this value in (2)

we get

F+5=2B+10

=2*25+10

=50+10

=60

So F=55...ANSWER