Math, asked by zehramadani7923, 5 hours ago

A father is 18years older than his son.ln 10years time, the father will be twice as old as the son.what is the son's present age.

Answers

Answered by ravitejadurki

0

Step-by-step explanation:

present

son's present age =x

Father age F=x+18

after 10 years

son's age =x+10

Father age F=2(x+10)

x+18=2(x+10)

x=8

present age of son = 8years

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