Question

A father is 20 years older than his son.12 years ago he was six times old his son. find their resent ages.

Answer 1

Step-by-step explanation:

Let the age of the father be x and let the age of the son be y.

x=y+20---->1

So twelve years ago,the age of the father would be x-12 and the age of the son would be y-12

x-12=6(y-12)

x-12=6y-72

x-6y= -60--->2

By substituting 1 in 2,we get:

y+20-6y= -60

-5y=-80

y=16

x=36

So the age of the father is 36 years and the age of the son is 16 years.