Math, asked by booraraman, 1 year ago

a father is 20 years older than his son 12 years ago the age of father was 6 times that of his son find their present ages

Answers

Answered by Ayush111777
3
let the son's present age be x
then father's age is 20+x

A/Q,
12 years ago means sons age = x-12
father's age 12 years ago = 20+x-12

but it is said that it was 6 times sons age so,
6(x-12)=20+x-12
6x-72=8+x
6x-x=8+72
5x=80
x=80/5
=16

Therefore son's present age is x=16
father's present age =20+x=20+16=36
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