Question

a father is 20 years older than his son. five years ago, he was three times as old as his son. find their present age.
step by step explanation

Answer 1

Step-by-step explanation:

let the age of son five years ago be x

then five year ago his father's age was 3x

then his son's present age is x+5

then his father's present age is 20+x+5

then their present ages are=3x+x=(x+5)+(20+x+5)

=4x=2x+30

=4x-2x=30

=2x=30

=x=30/2=15

therefore,his son's present age is 15+5=20

and father's present age is 20+15+5=40