A father is 20 years older than the son in 5 years the father age will be 7years more then twice that of the son find their present age
Answers
Given :
- A father is 20 years older than the son in 5 years
- The father age will be 7years more then twice that of the son
To Find :
- Pesent age of father and son
Solution :
Let present age of father and son be x and y years.
Father's age = Son age + 20
x = y + 20 ------------> (1)
After 5 years age of father = 2 ( After 5 years age of son ) + 7
x + 5 = 2 ( y + 5 ) + 7
x + 5 = 2y + 10 + 7
x - 2y = 12 ----------> (2)
Substitute the value of "x" in equation 2, we get
⇒ x - 2y = 12
⇒ y + 20 - 2y = 12
⇒ -y = 12 - 20
⇒ -y = -8
⇒ y = 8
Putting the value of "y" in equation 1, we get
⇒ x = y + 20
⇒ x = 8 + 20
⇒ x = 28
•°• Hence,
- Age of Father (x) = 28 years
- Age of Son (y) = 8 years
A father is 20 years older than the son in 5 years the father age will be 7years more then twice that of the son. Find their present age.
Given :-
- A father is 20 years older than the son.
- In 5 years the father age will be 7 years more then twice that of the son.
To Find :-
- Present age of Father and the son.
Solution :-
Let, the age of son be "x"
the age of the father be "y"
According to the question
Father's age = Son's age + 20
y = x + 20 ---------------- (eq. 1)
After 5 years,
Age of son = x + 5
Age of Father = 2 ( age of son after 5 years ) + 7
y - 2x = 12 ---------------- (eq. 2)
Substitute the value of "y" in eq. 2, we get
Now, substitute the value of "x" in eq. 1, we get
y = x + 20
y = 8 + 20
Hence,