Math, asked by narsingrao64801, 10 months ago

a father is 20 years older then his son after 5 years the age of father will be twice that of his son find the present age of both​

Answers

Answered by azizalasha
6

Answer:

solved

Step-by-step explanation:

present son's age = s

present father's age = s+20

after 5 years

s+ 25 = 2(s+5)

2s+10 = s + 25

s = 15

son's age   = 15 years

fathers age = 35 years

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