Question

a father is 20years older than his son. 12 years ago, the age of the father was six times that of his son. find their present ages

Answer 1

let the age of son be x
father's age is 20+x
(20+x-12)=6(x-12)
8+x=6x-72
5x=80
x=16
son=16
father=36

Answer 2

HEYA!!
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Let the present age of Son be X years .

Then the age of Father = X + 20 years .

Ages Twelve Years ago ,


( X + 20 - 12 ). = 6 ( X - 12 )

( X + 8 ) = 6X - 72

X + 8 - 6X + 72 = 0

- 5 X + 80 = 0

5 X = 80

X = 1 6


➡Age of Son = 16 years .

➡Age Of Father = 36 years


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