Math, asked by sarkartanisha, 10 months ago

A father is 24 years older than his daughter.In 4 years the father will be thrice as old as his daughter. find their present ages.​

Answers

Answered by wwwchandapandey15
9

Answer:

x=present age of daughter

x+24=present age of father

..

in 4 yrs

x+4=age of daughter

x+24+4=x+28=age of father

x+28=3(x+4)

x+28=3x+12

2x=16

x=8

x+24=32

present age of daughter=8

present age of father=32

Answered by hoangphannguyen
4

Answer:

Step-by-step explanation:

The father is 24 years older than his daughter.In 4 years, he will be thrice as old as his daughter.Find their present age.

***

x=present age of daughter

x+24=present age of father

..

in 4 yrs

x+4=age of daughter

 

x+24+4=x+28=age of father

x+28=3(x+4)

x+28=3x+12

2x=16

x=8

x+24=32

present age of daughter=8

present age of father=32

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