A father is 24 years older than his daughter in four year he will be thrice as old as his daughter find their present ages
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Let present age of
• daughter = x
• father = x + 24
×××××××××××××××××××
After 4 years,
Daughter's age = x + 4
Father's age = x + 24 + 4 = x + 28
According to the question,
3(x + 4) = x + 28
3x + 12 = x + 28
3x - x = 28 - 12
2x = 16
x= 16/2
x = 8
=============={
Then,
Present age of
• daughter = x = 8 years
• father = x + 24 = 8+24 = 32 years
I hope this will help you
(-:
• daughter = x
• father = x + 24
×××××××××××××××××××
After 4 years,
Daughter's age = x + 4
Father's age = x + 24 + 4 = x + 28
According to the question,
3(x + 4) = x + 28
3x + 12 = x + 28
3x - x = 28 - 12
2x = 16
x= 16/2
x = 8
=============={
Then,
Present age of
• daughter = x = 8 years
• father = x + 24 = 8+24 = 32 years
I hope this will help you
(-:
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