Question

a father is 24 yrs older than his dAughter.four years hence,the father will be as thrice older as his daughter..find their present ages

Answer 1

Let x equal age of father
Let y equal age of daughter

X = y +24--------1
X+4 = (y+4)3
X+4= 3y+12
X-3y=8------------2

1 nd 2

X-y =24
-X+3y=-8 -2y=16


Y=8
X=32

Answer 2

ANSWER
========

Let the daughter's age be x

Father's age = x + 24

Age of daughter after 4 years = x + 4

Age of father after 4 years = x + 24 + 4 = x + 28

A.T.Q.
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After 4 years , father's age will be thrice of daughter's age then.

The EQUATION Formed
------------------------------------

=> x + 28 = 3 ( x + 4 )

=> x + 28 = 3x + 12

=> 3x - x = 28 - 12

=> 2x = 16

=> x = 16/2

=> x = 8

ANS
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The present age of daughter is 8 years.

The present age of father = 8 + 24 = 32 years.

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