Math, asked by kunalsinha1772, 1 year ago

a father is 25 years older than his son. ten years back the ratio between the ages of the father and the son was 2 : 1. the present age of the son is

Answers

Answered by Maitri345
0
Let son's age = x
So father's age = x + 25
Ten years before ,
Father's age = x +25 -10
= x + 15
Son's age = x - 10
A.T.Q.
x + 15/x - 10 = 2/1
1(x+15) =2(x-10)
x+15=2x-20
15+20=2x-x
35=x
So son's age=35
father's age= 35+25
=60
Hope it helps you
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