Math, asked by sumukhalraju0987, 9 months ago

A father is 25years old than his son. after 8 years the ratio of their ages will be 13:8 .find the present age​

Answers

Answered by Angie432
1

Answer:

Step-by-step explanation:

Let the age of son be x years.

Thus, age of father is x+25 years.

After 8 years, their ages will be

Age of son x+8 and age of father x+25+8=x+33.

The ratio of their ages is 13:8.

\frac{x + 33}{x + 8}  = \frac{13}{8}

​⇒8(x+33)=13(x+8)

⇒8x+264=13x+104

⇒13x−8x=264−104

⇒5x=160

⇒x=32

Age of son is 32 years.

Thus, age of father is x+25=32+25=57 years.

Answered by Anonymous
8

let the son's age be x

father's age=x+25

after 8 years their ages

son's age =x+8

father's age =x+25+8 (add them)

the ratio of their ages is 13:8

therefore, x+33/x+8 (divide them)

=13/8

8(x+33)= 13(x+8)

8x+264=13x+104

5x=160

x=32

age of son =32

Thus, the father's age is x+25=32+25=57 years

Hope it helps you brainliest and thanks

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