Question

A father is 28 years older than his son. In 4 years he will be twice as old as his
son. Find their present ages.

Answer 1

Answer:

le the age of son be x yrs

hence,father's age is x+28

in 4 yrs,son=x+4

father=x+28+4

2(x+4)=x+32

2x+8=x+32

x=32-8=24

hence,sons age is 24 yrs

father's age is 24+28=52yrs

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