Question

a father is 28 years older than the son .in 5 years,the fathers age will be 7 years more than twice that of a son .find the present ages.

Answer 1

Hii Mate !!

Here is your answer :

Solution :

Let present ages of Father and son be X and Y year's.

Father age = Son age + 28 [ Given ]

X = Y + 28 -----(1)

And,

After 5 years age of father = 2 ( After 5 years age of son ) + 7 .

X + 5 = 2( y + 5 ) + 7

x + 5 = 2y + 10 + 7

x - 2y = 12 ------(2)

Substitute the value of X in equation (2) , we get

x - 2y = 12

y + 28 - 2y = 12

-y = 12 - 28

-y = -16

y = 16.

Putting the value of Y in equation (1) , we get

x = y + 28 = 16 + 28

x = 44.

Hence,

Age of father = X =
44 years.

And,

Age of son = Y = 16. year's.

♥ Hope it helps you ♥

By Rishi 403.

BeBrainly..

Answer 2

heyy

hope it's useful

thank me