Question

A father is 28years older than his daughter. In 2years' time he will be 3 times as old as his daughter. find their present ages.

Answer 1

Answer:

Step-by-step explanation:Lets the daughters age be= x

Father=28 + x

Daughter= x

In 2 years,

Father=28+2+x

Daughter=x+2

Equation:

30+x=3(x+2)

30+x=3x+6

2x=24

x=12

Present ages:

Father=40 years

Daughter=12 years

Answer 2

Answer:

so

let the age of the daughter be x

father= x+ 28

after 2 years

daughter= x+ 2

father= x+28+2

= x+ 30

=x+30 =3(x+2)

=x + 30 = 3x+6

=30-6=3x-x

=24=2x

=24/2=x

=12=x

daughters age = 12

fathers age= x+ 28

= 12+28

=40

so that's your answer

thnku