a father is 3 time older than his son's age. sum of their ages is 44 years. find their ages
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Answered by
1
let's son age equal to X
father age = 3x
x+3x=44
4x=44
x=44/4
x =11
henceson age equal to 11 year
father age equal to 11 .3=33years
Answered by
0
Answer:
son's age = 11 years
father's age = 33 years
Step-by-step explanation:
let son's age be x
let father's age be 3x
x + 3x = 44
4x = 44
x = 44 / 4
x = 11
son's age = x
= 11
father's age = 3x
= 3 × 11
= 33
so father's age = 33
son's age = 11
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