Math, asked by gagandeep485, 11 months ago

a father is 3 times as old as his son. after 15 years he will be twice as old as his son what are their present ages

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Answers

Answered by achulbul
0

Step-by-step explanation:

Let the age of son = x.

Then the age of man will be 3 times as old as his son = 3x.

After 15 years:

Age of son = x + 15.

Age of man = 3x + 15.

Given that Man will be only twice as old as his son.

3x + 15 = 2(x + 15)

3x + 15 = 2x + 30

3x = 2x + 15

x = 15.

Therefore the age of son = 15 years.

the age of man = 45 years.

Hope this helps!

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