A father is 3 times as old as his son. After 15 years, he will be twice as old as his son, what are their present ages.
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Let the present age of son be x
then father be 3x
After 15 years
3x + 15 = 2{x+15}
3x + 15 = 2x + 30
3x - 2x = 30-15
x = 15 years = son's present age
father present age = 3x15= 45 years
then father be 3x
After 15 years
3x + 15 = 2{x+15}
3x + 15 = 2x + 30
3x - 2x = 30-15
x = 15 years = son's present age
father present age = 3x15= 45 years
Answered by
12
hope this will be helpful
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