Question

A father is 3 times as old as his son. In 10 years time, will be double his son's age. Find their prescut ages a his age

Answer 1

Answer:

Now solving we get

X+10 = 2y+20

=3y +10= 2y+20(putting the value of x from 1st condition)

Y =10.

X= 3y= 30.

Father’s age is 30 and son’s age is 10.

Thank u.