A father is 3 times as old as his son. In 10 years times, he will be double of his son's age. Find their present ages
Answers
Not sure what the ratio method is, but if you set the father’s age as y and the son’s age as x then you can write the equations y= 3x (bc the father is currently three times as old as the son) and y+10=2(x+10) (bc in ten years the father will be twice as old as the son). If you swap the Y in the second equation with 3x (bc as we proved in the first equation 3x=y) and distribute the 2 to the x and the 10 you get 3x+10=2x+20. Now subtract 10 from both side and 2x from both sides and you get x=10. Plug 10 in for x in the first equation (y=3x) and you get y=30. So now you know the son is 10 and the father is 30.
Answer:
father=30yr
son =10yr
Step-by-step explanation:
let present ages of father and son be x yr and y yr respectively
According to first condition,
x=3y..........(1)
According to second condition,
x+10=2(y+10)
x+10=2y+20
x-2y+10-20=0
x-2y-10=0
3y-2y-10=0....(from 1)
y-10=0
y=10
putting value of y in (1)
x=3(10)
x=30
Present ages of father and son are 30yr and 10yr respectively