A father is 3 times as old as his son. In 10 years times, he will be double of his son's age. Find their present ages
Answers
Step-by-step explanation:
Let the present age of son =x
Then, the present age of father =3x
According to the question,
The age of son after 12 years =x+12
And the age of father after 12 years =2(x+12)
Therefore,
3x+12=2(x+12)
3x+12=2x+24
x=12
So, the present age of son is 12 years and present age of father is 36 years.
Answer:
Not sure what the ratio method is, but if you set the father’s age as y and the son’s age as x then you can write the equations y= 3x (bc the father is currently three times as old as the son) and y+10=2(x+10) (bc in ten years the father will be twice as old as the son). If you swap the Y in the second equation with 3x (bc as we proved in the first equation 3x=y) and distribute the 2 to the x and the 10 you get 3x+10=2x+20. Now subtract 10 from both side and 2x from both sides and you get x=10. Plug 10 in for x in the first equation (y=3x) and you get y=30. So now you know the son is 10 and the father is 30.