Question

a father is 3 times as old as his son in 10 yrs time his age will be double his son's age . find their present ages​

Answer 1

Answer:

Its Easyy..

Lets assume father's age be x and son’s age be y.

Then according to first condition x=3y. And according to 2nd condition x+10=2(y+10)

Now solving we get

X+10 = 2y+20

=3y +10= 2y+20(putting the value of x from 1st condition)

Y =10.

X= 3y= 30.

Father’s age is 30 and son’s age is 10.