Math, asked by Ruthwik1320, 9 months ago

A father is 3 times as old as his son. In 12 years times he will be twice as old as his son. Find the present ages of father and son.\

Answers

Answered by Sauron
41

\mathfrak{\large{\underline{\underline{Answer :- }}}}

The Presnet Ages of Father and Son are 36 years and 12 Years respectively.

\mathfrak{\large{\underline{\underline{Explanation :-}}}}

Given :

Presently, Father is 3 times old as his son

12 years later, Father will be twice the age of Son.

\textbf{\small{\underline{Consider the Present ages as -}}}

  • Son as x
  • Father as 3x

\textbf{\small{\underline{12 Years later -}}}

  • Son will be (x + 12)
  • Father will be (3x + 12)

\textbf{\small{\underline{According to the Question -}}}

After 12 years, father will be twice as old as his son.

\boxed{\bf{(3x + 12) = 2(x + 12)}}

\longrightarrow (3x + 12) = 2(x + 12)

\longrightarrow 3x + 12 = 2x + 24

\longrightarrow 3x - 2x = 24 - 12

\longrightarrow x = 12

Son's present age is 12 Years.

\rule{300}{1.5}

Value of 3x

\longrightarrow 3 × 12

\longrightarrow 36

Father's present age is 36 years.

\therefore The Presnet Ages of Father and Son are 36 years and 12 Years respectively.

\rule{300}{1.5}

\mathfrak{\large{\underline{\underline{Verification :-}}}}

Place the Value of x in the Equation and check of both the sides of the equation are same or not.

\longrightarrow (3x + 12) = 2(x + 12)

\longrightarrow 3(12) + 12 = 2(12 + 12)

\longrightarrow 36 + 12 = 24 + 24

\longrightarrow 48 = 48

\longrightarrow LHS = RHS

\therefore The Presnet Ages of Father and Son are 36 years and 12 Years respectively.


Anonymous: Nice :)
Sauron: Thankies Krishna ! ❤️
Answered by Anonymous
33

Answer:-

Present age of son = 12 years

Present age of Father = 36 years

Explanation:-

Given

Father age = 3 times the age of son

After, 12 years

father age = 2 times the age of son

To Find

Present ages of son and father

Solution

Let,

son's age be x

fathers's age be 3x

After 12 years

Age of father = (3x+12) years

Age of son = (x+12) years

Acc. to the question

\mathsf{3x+12 = 2(x+12)}

\mathsf{3x+12 = 2x+24}

\mathsf{3x -2x = 24 - 12}

\mathsf{ x = 12}

Present age of son = 12 years

Now

Father's present age = 3x

Father's present age = 3(12) = 36 years

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