A father is 3 times as old as his son. In 12 years times he will be twice as old as his son. Find the present ages of father and son.\
Answers
The Presnet Ages of Father and Son are 36 years and 12 Years respectively.
Given :
Presently, Father is 3 times old as his son
12 years later, Father will be twice the age of Son.
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- Son as x
- Father as 3x
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- Son will be (x + 12)
- Father will be (3x + 12)
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After 12 years, father will be twice as old as his son.
★
(3x + 12) = 2(x + 12)
3x + 12 = 2x + 24
3x - 2x = 24 - 12
x = 12
Son's present age is 12 Years.
★ Value of 3x
3 × 12
36
Father's present age is 36 years.
The Presnet Ages of Father and Son are 36 years and 12 Years respectively.
Place the Value of x in the Equation and check of both the sides of the equation are same or not.
(3x + 12) = 2(x + 12)
3(12) + 12 = 2(12 + 12)
36 + 12 = 24 + 24
48 = 48
LHS = RHS
The Presnet Ages of Father and Son are 36 years and 12 Years respectively.
Answer:-
Present age of son = 12 years
Present age of Father = 36 years
Explanation:-
Given
Father age = 3 times the age of son
After, 12 years
father age = 2 times the age of son
To Find
Present ages of son and father
Solution
Let,
son's age be x
fathers's age be 3x
After 12 years
Age of father = (3x+12) years
Age of son = (x+12) years
Acc. to the question
Present age of son = 12 years
Now
Father's present age = 3x
Father's present age = 3(12) = 36 years