A father is 3 times as old his son.after 5 years his age is 2 and a dual times as old as his son.represent this situation algebrically
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Let the age of the son be x, then father's age is 3(x).
after five years, son's age becomes (x+5) and father's age becomes 2(x+5) + 2.
Father's age can also be taken as 3(x) + 5.
So, [ 3(x) + 5 ] = 2(x+5) + 2
after five years, son's age becomes (x+5) and father's age becomes 2(x+5) + 2.
Father's age can also be taken as 3(x) + 5.
So, [ 3(x) + 5 ] = 2(x+5) + 2
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