Question

a father is 3 times as older as his son . after 15 years , he will be twice as old as his son . find their present ages​

Answer 1

Let the age of son = x.

Then the age of man will be 3 times as old as his son = 3x.

After 15 years:

Age of son = x + 15.

Age of man = 3x + 15.

Given that Man will be only twice as old as his son.

3x + 15 = 2(x + 15)

3x + 15 = 2x + 30

3x = 2x + 15

x = 15.

Therefore the age of son = 15 years.

the age of man = 45 years.

Hope this helps!

Answer 2

Answer:

Here is your answer:

Let the present age of son be X years

then the present age of father be 3X years

After 15 years

Son's age = (X + 15) years

and father's = (3X + 15)

According to the question, we have

=> (3X + 13) = 2(X + 15)

=> 3X + 15 = 2X + 30

=> 3 X - 2 X = 30 - 15

=> X = 15

.°. The present age of son = 15 years

and present age of father = 3X = 15 × 3 = 45 years.

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