Math, asked by balbirajumal123456, 7 months ago

A father is 3 times oldAs his

son. After 15 years, He’ll be twice

as old as his son What are the

present age​

Answers

Answered by Anonymous
2

let the present age of son be x

present age of father will be 3x

After 15 years

age of son will ne x + 15

age of father will be 2(x + 15) = 2x + 30

x + 3x = x + 15 + 2x + 30

4x = 3x + 45

4x - 3x = 45

x = 45

therefore present age of son = x = 45

present age of father = 2x = 90

Answered by nirali17455w
1

Step-by-step explanation:

LET THE AGE OF THE SON BE x .

SO, THE AGE OF THE MAN IS 3x.

AFTER 15 YEARS,

SON'S AGE= x+15

MAN'S AGE =3x+15

AS PER QUESTION,

3x+15 = 2(x+15)

=> 3x+15= 2x+30

=> 3x-2x = 30-15

=> x = 15

3x= 3×15 = 45.

Similar questions