Question

A father is 3 times son's age and the sum of their ages is 100, therefore Son's age is _________years.

Answer 1

Your Solution:

Let the Age of son be "y" years.

Then the age of Father is 3y years.(3 times of son)

ATQ, y + 3y = 100

4y = 100

» y = 100/4

» y = 25 years (Son's Age)

3y = 3 × 25 = 75 years (Father's Age)

∴ The age of son is 25 years.

I hope you got it.

Keep Learning & Keep Growing :)

Answer 2

$\large\mathscr \color{black}\colorbox{red}{\colorbox{orange}{\colorbox{yellow}{\colorbox{green}{\colorbox{blue}{\colorbox{indigo}{\colorbox{violet}{\underline {ANSWER}}}}}}}}$

$\large\tt\color{pink}{let\:the\:son's\:age\:be \:\bf{'x'}} \\ \\ \large\tt\color{pink}age \: of \: father = 3x \\ \\ \tt{x + 3x = 100} \\ \\ \tt4x = 100 \\ \\ \large\tt\color{lime}x = \underline{ \underline{ 25}}$

father