A father is 30 times older than his son. 18 years later, he will be only thrice as old as his son. Fathers present age?
Answers
Answered by
16
let the father age be = x
and the son age be= y
now according to 1st condition
x= 30y ........... ( -1 )
according to 2nd condition
x+18 = 3(y+18)
x-3y= 36. ............ (-2)
now using Eq 1 and 2
we get y = 36/27 =4/3 = 1.3 years
x = 40 years
here is Ur answer hope it will help u.
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and the son age be= y
now according to 1st condition
x= 30y ........... ( -1 )
according to 2nd condition
x+18 = 3(y+18)
x-3y= 36. ............ (-2)
now using Eq 1 and 2
we get y = 36/27 =4/3 = 1.3 years
x = 40 years
here is Ur answer hope it will help u.
plzz mark it as brainliest and follow me
Answered by
26
hey! your answer is here..
let son age be x
then the father age will be
30x
18 year later
30x+18=3(x+18)
30x+18=3x+54
30x-3x=54-18
27x=36
x=36/27
x=4/3
father age = 30x
= 30*4/3
=40
hope it helps......
let son age be x
then the father age will be
30x
18 year later
30x+18=3(x+18)
30x+18=3x+54
30x-3x=54-18
27x=36
x=36/27
x=4/3
father age = 30x
= 30*4/3
=40
hope it helps......
shravanvannela12:
Thanks
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