Question

.A father is 30 years elder than his son. After 8 years, he will be 4 times as old as his son. Find their present ages.​

Answer 1

Father = 32 years

Son = 2 years

Step-by-step explanation:

Given -

• Father is 30 years elder than his son.
• After 8 years, the father will be 4 times as old as his son.

To find -

• Their present ages.

Solution -

Let the age of father be 'x' years.

Let the age of his son be 'y' years.

According to the first statement ,

x = y + 30--------1

Now , according to the second statement,

x + 8 = (y + 8)4

→ x + 8 = 4y + 32

→ y + 30 + 8 = 4y + 32 (from 1)

→ y + 38 = 4y + 32

→ 38 - 32 = 4y - y

→ 6 = 3y

→ 6/3 = y

→ 2 years = y (putting in 1)

x = 2 + 30

x = 32 years

Therefore, the present age of the father is 32 years and the present age of his son is 2 years.

Answer 2

Answer:

Let the present age of the son be x years

Then father's age will be (x+30) years

Given after 12 years father will be three times as old as his son

Therefore,

(x+12)3=x+30+12

3x+36=x+42

3x−x=42−36

2x=6

x=3

x+30=3+30=33

So, the present age of son is 3 years and present age of the father is 33 years