A father is 30 years older than his son.10 years ago,the age of the son was 1/4th that of his father.find their ages.
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Let the age of son be x
So,father's age=x+30
10years ago,
Son's age=1/4 x (x+20)=x+20/4 yrs
Father's age =x+20 yrs
A/Q
x+20/4=x-10
x+20=4x-40
x-4x=-40-20
-3x=-60
x=20.
Therefore,son's age=20yrs and father's age=x+30
20+30=50yrs
So,father's age=x+30
10years ago,
Son's age=1/4 x (x+20)=x+20/4 yrs
Father's age =x+20 yrs
A/Q
x+20/4=x-10
x+20=4x-40
x-4x=-40-20
-3x=-60
x=20.
Therefore,son's age=20yrs and father's age=x+30
20+30=50yrs
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