Question

A father is 30 years older than his son. 12 years from now, the father will be twice as old as his son then. Find their age at present.

Answer 1

Step-by-step explanation:

ler the present age of son be x,

and father be x+30

12 years hence,

2(x+12)=x+30+12

2x+24 =x+42

2x-x=42-24

so, x= 18

Answer 2

Answer:

Present Age of Father= 48 years

Present Age of Son= 18 years

Step-by-step explanation:

Let, Present Age of Son= x years

Then, Present Age of Father= (x+30) years

12 years from now,

Son's Age= (x+12) years

Father's Age= (x+30+12) = (x+42) years

Now According to Question,

Father's Age = 2× Son's Age

(x+42)=2×(x+12)

x + 42 = 2x + 24

now changeing the sides,

42-24 = 2x - x

18 = x

or x = 18

Hence, Present Age of Son= x = 18 years

and Present Age of Father= (x + 30) = (18+30)=

48 years

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