Question

A father is 30 years older than his son. After five years the man will be four times as old as his son. find their present ages.​

Answer 1

Step-by-step explanation:

Let the present age of the son be x years

Then father's age will be (x+30) years

Given after 12 years father will be three times as old as his son

Therefore,

(x+12)3=x+30+12

3x+36=x+42

3x−x=42−36

2x=6

x=3

x+30=3+30=33

So, the present age of son is 3 years and present age of the father is 33 years

Answer 2

Answer:

The son's present age= 5 yrs

The father's present age= 35 yrs

Step-by-step explanation:

Let present age of the son be 'x' yrs

Then present age of the father will be 'x+30' yrs

After 5 yrs,

Son's age= 'x+5' yrs

Father's age= 'x+35' yrs

A/q,

x+35=4(x+5)

=> x+35=4x+20

=> -3x=-15

=> 3x=15

=> x=(15/3)

=> x=5

Therefore,

The son's present age= 5 yrs

The father's present age= 35 yrs