Math, asked by pranjalikothawade123, 6 hours ago

A father is 30 years older than his son, and one year ago he was four times as old as his son. Find the father’s present ages.​

Answers

Answered by shalakakothawade123
3

Step-by-step explanation:

Let x be the present age of his son.

Age of father = 30 + x

One year ago,

Son's age = x - 1

Father's age = 30 + x - 1

Father's age = 29 + x

29 + x = 4(x - 1)

29 + x = 4x - 4

4x - x = 29 + 4

3x = 33

x = 11

Father's present age = 30 + 11

= 43

So, the father's present age is 43 years.

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