Question

.. A father is 30 years older than his son, and one year ago he was four times as old as his son. Find their present ages?​

Answer 1

Answer:

father age 41 and son age 11

Step-by-step explanation:

let father age be x and son age be y

x-y=30 eq i

one year ago

x-1= 4(y-1)

x-1= 4y-4

x-4y=-3 eq ii

eq i - eq ii

x-y-(x-4y)=30-(-3)

x-y-x+4y=30+3

3y=33

y=11

substituting this value in eq i

x-y=30

x-11=30

x=30+11

x=41

Answer 2

Answer

father age 41 and son age 11

step- by- step explanations

let father age be x and Son age be y

x -y= 30egi

1 year ago

x-1=4(y-1)

x-4y=-3 e g i

e g i-e g i

x-y-(x-4y)=30-(-3)

x-y-x+4y=30+3

3y=33

y=11