Math, asked by monica91, 11 months ago

a father is 30 years older than his son find their present ages​

Answers

Answered by mehakdhull
0

Step-by-step explanation:

ur question is incomplete

Answered by Maitrayeepareek
2

Hii Mate !!

Here is your answer :

Solution :

Let present ages of Father and son be X and Y year's.

Father age = Son age + 30 [ Given ]

X = Y + 30 -----(1)

And,

After 12 years age of father = 3 ( Age of son after 12 years ).

X + 12 = 3 ( y + 12 )

x + 12 = 3y + 36.

x - 3y = 24 -----(2)

Substitute the value of X in equation (2) , we get

x - 3y = 24

y + 30 - 3y = 24

-2y = -6

y = 3.

Putting the value of Y in equation (1) , we get

x = y + 30 = 3 + 30

x = 33.

Hence,

Age of father = X = 33 years.

And,

Age of son = Y = 3 year's.

♥ Hope it helps you ♥

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