a father is 30 years older than his son. in 12 years, the man will three times as old as his son find their present ages.
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x be father age and y be son age
x = y + 30
and x + 12 = 3 (y + 12)
now
substituting the value of x
y + 42 = 3y + 36
2y = 6
y = 3
x = 33
x = y + 30
and x + 12 = 3 (y + 12)
now
substituting the value of x
y + 42 = 3y + 36
2y = 6
y = 3
x = 33
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