Question

a father is 30 years older than his son. In 12 years, the man will be three times as as his son. Find their present ages.​

Answer 1

Answer

Let the current age of the son be x years old.

Current age of father = x+30

In 12 years:

Final age of father = (x+30)+12=x+42

Final age of son = x+12

Now since we know that the final age of the father is three times the final age of the son:

x+42=3(x+12)

x+42=3x+36

2x=42−36=6

x=3

x+30=3+30=33

Therefore, the current age of the son is 3 years old and the current age of the father is 33 years old.

Step-by-step explanation:

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Answer 2

$\sf\underline{Question}$

A father is 30 years older than his son. In 12 years, the man will be three times as as his son. Find their present ages.

$\sf\underline{Answer}$

• A father is 30 years older than his son (given)
• Let age of son be 'x'
• Then, age of father becomes x + 30
• In 12 years, age of man will be three times the age of his son
• Age of son after 12 years = x + 12
• Age of man after 12 years = x + 30 + 12 = x + 42

As the man is three times older than his son in 12 yrs,

x + 42 = 3(x + 12)

x + 42 = 3x + 36

x - 3x = 36 - 42

-2x = -6

2x = 6

x = $\sf\frac{6}{2}$

x = 3

Therefore, the present age of son is 3 years

Present age of man = 3 + 33 = 36

Therefore , the present age of man is 36 years