Question

A father is 30 years older than his son . In 12 years ,the man will be three times as old as his son find their present ages

Answer 1

Let present age of his son be X year's.


Present age of father = ( X + 30 ) year's.


After 12 year's age of father = ( X + 30 + 12 ) = ( X + 42 ) year's.



After 12 year's age of son = ( X + 12 ) year's.



According to the question,


( X + 42 ) = 3 ( X + 12 )


X + 42 = 3X + 36



3X - X = 42 - 36


2X = 6


X = 3 years.


Present age of son = x = 3 years


and,


present age of father = 33 year's

Answer 2

Let present age of son be x

Given present age of father then = x + 30


After 12 years son = x + 12

After 12 years father = x + 30 + 12 = x + 42

But given after 12 years, father = 3(x + 12) = 3x + 36

=> x + 42 = 3x + 36

=> x - 3x = 36 - 42

=> -2x = -6

=> x = -6/-2

=> x = 3


Present age of son = 3yrs

Present age of father = x + 30 = 3 + 30 = 33yrs


Hope it helps dear friend ☺️✌️