a father is 30 years older than his son in 12 years the man will be three times old as his son find their present ages
Answers
Answered by
6
Hii Mate !!
Here is your answer :
Solution :
Let present ages of Father and son be X and Y year's.
Father age = Son age + 30 [ Given ]
X = Y + 30 -----(1)
And,
After 12 years age of father = 3 ( Age of son after 12 years ).
X + 12 = 3 ( y + 12 )
x + 12 = 3y + 36.
x - 3y = 24 -----(2)
Substitute the value of X in equation (2) , we get
x - 3y = 24
y + 30 - 3y = 24
-2y = -6
y = 3.
Putting the value of Y in equation (1) , we get
x = y + 30 = 3 + 30
x = 33.
Hence,
Age of father = X = 33 years.
And,
Age of son = Y = 3 year's.
♥ Hope it helps you ♥
By Rishi 403.
BeBrainly..
Here is your answer :
Solution :
Let present ages of Father and son be X and Y year's.
Father age = Son age + 30 [ Given ]
X = Y + 30 -----(1)
And,
After 12 years age of father = 3 ( Age of son after 12 years ).
X + 12 = 3 ( y + 12 )
x + 12 = 3y + 36.
x - 3y = 24 -----(2)
Substitute the value of X in equation (2) , we get
x - 3y = 24
y + 30 - 3y = 24
-2y = -6
y = 3.
Putting the value of Y in equation (1) , we get
x = y + 30 = 3 + 30
x = 33.
Hence,
Age of father = X = 33 years.
And,
Age of son = Y = 3 year's.
♥ Hope it helps you ♥
By Rishi 403.
BeBrainly..
Answered by
1
heyy
hope it's useful
follow me
give thanks
Attachments:
Similar questions
Geography,
6 months ago
Math,
6 months ago
Math,
6 months ago
Math,
11 months ago
Social Sciences,
11 months ago
Political Science,
1 year ago