Math, asked by prateeksingh22, 11 months ago

a father is 30 years older than his son in 12 years the man will be three times old as his son find their present ages

Answers

Answered by BrainlyMOSAD
6
Hii Mate !!


Here is your answer :



Solution :


Let present ages of Father and son be X and Y year's.



Father age = Son age + 30 [ Given ]


X = Y + 30 -----(1)

And,


After 12 years age of father = 3 ( Age of son after 12 years ).


X + 12 = 3 ( y + 12 )


x + 12 = 3y + 36.


x - 3y = 24 -----(2)


Substitute the value of X in equation (2) , we get


x - 3y = 24


y + 30 - 3y = 24



-2y = -6


y = 3.


Putting the value of Y in equation (1) , we get

x = y + 30 = 3 + 30


x = 33.


Hence,


Age of father = X = 33 years.


And,


Age of son = Y = 3 year's.


♥ Hope it helps you ♥



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1

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