a father is 30year older then his son in 12 year the man will be three times as old as his son find their parents age
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let the present age of the father = x
present age of the son = y
x - y = 30 ----------1
after 12 years,
father's age = x + 12
son's age = y + 12
A.T.Q
x + 12 = 3(y + 12)
x +12 = 3y + 36
x - 3y = 24 --------2
1×3 - 2
3x - 3y = 90
-x + 3y = -24
---------------------
2x = 66
x = 33
by putting the value of x in eq 1
y = 33 - 30 = 3
Hence,
present age of father = 33 years
present age of son = 3 years
Hope it helps!!
present age of the son = y
x - y = 30 ----------1
after 12 years,
father's age = x + 12
son's age = y + 12
A.T.Q
x + 12 = 3(y + 12)
x +12 = 3y + 36
x - 3y = 24 --------2
1×3 - 2
3x - 3y = 90
-x + 3y = -24
---------------------
2x = 66
x = 33
by putting the value of x in eq 1
y = 33 - 30 = 3
Hence,
present age of father = 33 years
present age of son = 3 years
Hope it helps!!
surbhi06:
class 10
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