Question

A father is 30years old than his son 20years the father will be twice as old as his son . find the present age

Answer 1

Answer:

Step-by-step explanation:

father's age = x

boy's age = y

x = y + 30

after 20 years

father's age = x + 20

boy's age = y + 20

x+ 20 = 2(y + 20)

(y + 30) + 20 = 2(y + 20)

y + 50 = 2y + 40

y = 10

x = 10 + 30

x = 40

so father's age is 40 years

boy's age is 10 years

Answer 2

Answer:

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