Math, asked by Alkhanjari98us, 4 months ago

A father is 36 years older than his son. After 4 years the father will be four times as old as his son. Find the present ages of the father and his son. *

Answers

Answered by jandubhavya78
1

Answer:

Step-by-step explanation:

age of his father is 36

4x=36

36/4

9

age of his son =9

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Answered by nikitanayak2500
2

Answer:

let the age of son is x

father is 36 years older than his son

then the age of father is =x+36

after 4 yrs son's age is=x+4

after 4 yrs fathers age is=x+36+4=x+40

father's age is 4 times than that of son's

then

4(x+4)=x+40

4x+16=x+40

3x=24

x=8

son=8

father=8+36=44

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