Math, asked by rakshit9652, 1 year ago

a father is 3times his son age. six years ago he was the five times of his son age find the present age of the father and his sons

Answers

Answered by bk013558
1

Answer:let son age to be x

then father =3x


six year ago,

son=x-6

father =3x-6

A/Q

3x-6=5 (x-6)

3x-6=5x-30

5x-3x=30-6

2x=24

x=24/2

x=12


present age,

son = 12 years

then father =36


Step-by-step explanation:


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