Question

A father is 4 times as old as his son, 5 years ago the sum of their age was 70, find their present age​

Answer 1

Easiest way to do do such type of questions is that there is always two cases in them and we just have to change them into two equations.

let's see:)

let the father's age be x

and son's age be y

First Case:-

x=4y

Second Case:-

(x-5)+(y-5)=70

After solving both the equations:-

x=64

y=16

Answer 2

Answer:

Present age of son $=16$ years

Present age of father $=64$ years .

Step-by-step explanation:

Given the relation between the ages of a father and his son. We are asked to find their present ages.

From the given information, father's age is four times as old as his son.

Mathematically writing,

let the age of son be $x$ ,

then the age of father $=4x$.

Five years ago sum of their age was $70$ .

Five years ago age of son  $=x-5$ , age of father $4x-5$ .

Therefore

         $(4x-5)+(x-5)=70\\\\4x+x-5-5=70\\\\5x-10=70\\\\x=80/5=16$

Thus present age of son $16$ years

Present age of father $4*16=64$ years.

Five years ago age of son $11$ years , age of father $59$ years and their sum is

$11+59=70$

Hence the answer.

thank you