Math, asked by prethiga, 10 months ago

A father is 4 times as old as his son. 5 years hence father will be three times the age of his son find their present age

Answers

Answered by karora1496
0
Let present age,

sons's age = x

father's age = 4x

5 years hence (i.e. after)

son's age = x+5

father's age = 4x+5

4x+5 = 3(x+5)

4x+5 = 3x+15

4x-3x = 15-5

x = 10

Present age of son = x =10 years

Present age of father = 4x = 4×10 = 40 years

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