A father is 4 times as old as his son. In 14 years time he will be twice as old as his son. How old are they now?
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Answer:son is 7 years while the father is 28 years
Step-by-step explanation:
Let f=father's current age
Let s=son's current age
F=4s
F+12=2(s+14)
F+14=2s+28
I will iluse the substitution method to replace f with 4s
4s+14=2s+28
2s+14=28
2s=14
s=14/2
S=7
Therefore son 7 and father 28
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Answer:
Step-by-step explanation:
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