Question

a father is 4 times as old as his son in 20 years the fater will be twice as old as his son find present age of each​

Answer 1

Answer:

Let the present age of the son = x years

Present age of the father = 4x years

After 20 years,

Son’s age will be (x + 20) years

and Father’s age will be (4x + 20) years

According to the condition,

4x+20=2(x+20)4x+20=2(x+20)

4x+20=2x+40⇒ 4x+20=2x+40

4x-2x=40-20⇒4x−2x=40−20

2x=202x=20

⇒x=\frac{20}{2}⇒x=220

⇒x=10⇒x=10

∴Present age of the son is10 years and

Present age of the father is = 4x=4\times10=404x=4×10=40 years

Step-by-step explanation:

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Answer 2

Answer:

10 years, 40 years

Step-by-step explanation:

Let the present age of the son = x years

Present age of the father = 4x years

After 20 years,

Son’s age will be (x + 20) years

and Father’s age will be (4x + 20) years

According to the condition,

4x + 20 = 2(x + 20)

=> 4x + 20 = 2x + 40

=> 4x - 2x = 40 - 20

=> 2x = 20

=> x = 20/2

=> x = 10

So,

Present age of the Son = 10 years

Present age of the father = 4×10 years = 40 years