Math, asked by upadhyaynavneet521, 9 months ago

A father is 4 times elder then his daughter.After 16 year age of father is just 2 times his daughter.what is the age of his daughter?

Answers

Answered by rekha20011978
6

Answer:

age of the daughter is 8

Step-by-step explanation:

let the age of :-

daughter =x. ; father = 4x

after 16 yrs,the age of :-

daughter= x + 16

father = 4x+16

according to the question

4x+16=2(x+16)

=> 4x +16 = 2x+32

=> 4x-2x= 32-16

=> 2x= 16

x => 16/2= 8

therefore daughter's age = 8

hope it helps you

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Answered by shivansht2005
0

let the daughter's age be x

man's age= 4x

after 16 years,

man's age = 4x+16

daughters age= x+16

therefore the equation is,

2(x+16)= 4x+16 (since the man will be twice the age of his daughter)

2x+32=4x+16

4x+16=2x+32

4x-2x= 32-16

2x= 16

x=16/2

x=8

therefore daughters present age will be 8 years

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